16[4-(3-2x)]+8x=5(8x+5)-9

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Solution for 16[4-(3-2x)]+8x=5(8x+5)-9 equation:


Simplifying
16[4 + -1(3 + -2x)] + 8x = 5(8x + 5) + -9
16[4 + (3 * -1 + -2x * -1)] + 8x = 5(8x + 5) + -9
16[4 + (-3 + 2x)] + 8x = 5(8x + 5) + -9

Combine like terms: 4 + -3 = 1
16[1 + 2x] + 8x = 5(8x + 5) + -9
[1 * 16 + 2x * 16] + 8x = 5(8x + 5) + -9
[16 + 32x] + 8x = 5(8x + 5) + -9

Combine like terms: 32x + 8x = 40x
16 + 40x = 5(8x + 5) + -9

Reorder the terms:
16 + 40x = 5(5 + 8x) + -9
16 + 40x = (5 * 5 + 8x * 5) + -9
16 + 40x = (25 + 40x) + -9

Reorder the terms:
16 + 40x = 25 + -9 + 40x

Combine like terms: 25 + -9 = 16
16 + 40x = 16 + 40x

Add '-16' to each side of the equation.
16 + -16 + 40x = 16 + -16 + 40x

Combine like terms: 16 + -16 = 0
0 + 40x = 16 + -16 + 40x
40x = 16 + -16 + 40x

Combine like terms: 16 + -16 = 0
40x = 0 + 40x
40x = 40x

Add '-40x' to each side of the equation.
40x + -40x = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 40x + -40x

Combine like terms: 40x + -40x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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